So, what you're looking for are the odds of: 1) Rolling a d20, and reading the result (let's say it results in a 7) 2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
[[deleted equation that doesn't want to copy/paste over nicely]]
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
So, what you're looking for are the odds of: 1) Rolling a d20, and reading the result (let's say it results in a 7) 2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
[[deleted equation that doesn't want to copy/paste over nicely]]
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
*round of applause*
28
Rollback Post to RevisionRollBack
pronouns (i/d/g/a/f) Six up, five oh, pigs come, I cop 'n go The blotter shows they got me on the rocks like Galapagos |------extended sig------|
Oooops, to big
Hello! Call me Tana or 타나
My pronouns are They/them (idc.)
I will always support you. Because that is my way of showing how much I care
Current List of Children: Golden, Salem, Wes, Aspen, Link, SuperDog, and Foalin.
I have Autism. And, you would probably call me Trans Femme, Pansexual pancake, and Ace
Current Dice Code: [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] = [roll][roll:-5]+[roll:-4]+[roll:-3]+[roll:-2]+[roll:-1][/roll]
16
How'd you get it that big?
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8 attempt: 5 + 5 + 7 + 5 = 22
Last to know and first to be blamed...
As a free action, can I regret my life choices?
17
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8 attempt: 2 + 7 + 4 + 3 = Unable to parse dice roll.
So, what you're looking for are the odds of:
1) Rolling a d20, and reading the result (let's say it results in a 7)
2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
Last to know and first to be blamed...
As a free action, can I regret my life choices?
*round of applause*
28
pronouns (i/d/g/a/f)
Six up, five oh, pigs come, I cop 'n go
The blotter shows they got me on the rocks like Galapagos
|------extended sig------|
4d8 attempt: 7 + 5 + 4 + 4 = 20
Last to know and first to be blamed...
As a free action, can I regret my life choices?
25
pronouns (i/d/g/a/f)
Six up, five oh, pigs come, I cop 'n go
The blotter shows they got me on the rocks like Galapagos
|------extended sig------|
4d8 attempt:3 + 5 + 1 + 5 = 14.
Hiii :3
14yo cancer, bisexual(maybe Pan?), Genderfluid femboy, prefer She/They but don’t mind what pronouns you call me
Love all soulsbourne and soulslike games + metroidvanias.
:2 + 6 + 2 + 8 = 18
Hello! Call me Tana or 타나
My pronouns are They/them (idc.)
I will always support you. Because that is my way of showing how much I care
Current List of Children: Golden, Salem, Wes, Aspen, Link, SuperDog, and Foalin.
I have Autism. And, you would probably call me Trans Femme, Pansexual pancake, and Ace
Current Dice Code: [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] = [roll][roll:-5]+[roll:-4]+[roll:-3]+[roll:-2]+[roll:-1][/roll]
20
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8=19
Hello! I am a perfectly sane gibberer. Hi! :D
Locations are dead, the Temple of Potassium has fallen but its ideals live on
A mysterious link of chain... (Extended signature). PRAISE JEFF THE EVIL ROOMBA! REALLY cool video.
One of the Warlock Patrons on the forums. Low, low price of your soul, firstborn child and liver!
Titles: The Echoing Story Spewer (Drummer), the Endless Maws (Isis), the Mad Murderer (PJ), more on my extended sig
:4 + 5 + 3 + 2 = 14
Hello! Call me Tana or 타나
My pronouns are They/them (idc.)
I will always support you. Because that is my way of showing how much I care
Current List of Children: Golden, Salem, Wes, Aspen, Link, SuperDog, and Foalin.
I have Autism. And, you would probably call me Trans Femme, Pansexual pancake, and Ace
Current Dice Code: [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] = [roll][roll:-5]+[roll:-4]+[roll:-3]+[roll:-2]+[roll:-1][/roll]
(For a 32!!) Roll 4d8 = 5 + 4 + 3 + 4= 16
Next is 6d4 ... soon I hope.
4d8 attempt: 6 + 3 + 2 + 3 = 14
Last to know and first to be blamed...
As a free action, can I regret my life choices?
:1 + 1 + 3 + 3 = 8
Hello! Call me Tana or 타나
My pronouns are They/them (idc.)
I will always support you. Because that is my way of showing how much I care
Current List of Children: Golden, Salem, Wes, Aspen, Link, SuperDog, and Foalin.
I have Autism. And, you would probably call me Trans Femme, Pansexual pancake, and Ace
Current Dice Code: [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] = [roll][roll:-5]+[roll:-4]+[roll:-3]+[roll:-2]+[roll:-1][/roll]
4d8 attempt: 5 + 5 + 5 + 4 = 19
Last to know and first to be blamed...
As a free action, can I regret my life choices?
(For a 32!!) Roll 4d8 = 6 + 5 + 1 + 5= 17
Next is 6d4 ... soon I hope.
4d8 attempt: 8 + 7 + 2 + 4 = Unable to parse dice roll.
Last to know and first to be blamed...
As a free action, can I regret my life choices?
:3 + 5 + 1 + 5 = 27
Hello! Call me Tana or 타나
My pronouns are They/them (idc.)
I will always support you. Because that is my way of showing how much I care
Current List of Children: Golden, Salem, Wes, Aspen, Link, SuperDog, and Foalin.
I have Autism. And, you would probably call me Trans Femme, Pansexual pancake, and Ace
Current Dice Code: [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] + [roll]1d6[/roll] = [roll][roll:-5]+[roll:-4]+[roll:-3]+[roll:-2]+[roll:-1][/roll]