Hello! Call me Tana or 타나 My pronouns are Any/All/BOC Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
This post has potentially manipulated dice roll results.
4d8 attempt: 2 + 7 + 7 + 1 = 17
So, what you're looking for are the odds of: 1) Rolling a d20, and reading the result (let's say it results in a 7) 2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
[[deleted equation that doesn't want to copy/paste over nicely]]
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
So, what you're looking for are the odds of: 1) Rolling a d20, and reading the result (let's say it results in a 7) 2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
[[deleted equation that doesn't want to copy/paste over nicely]]
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
*round of applause*
28
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Eleanor Rigby picks up the rice in the church where a wedding has been Lives in a dream, waits at the window Wearing the face that she keeps in a jar by the door—who is it for?
This post has potentially manipulated dice roll results.
22
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Eleanor Rigby picks up the rice in the church where a wedding has been Lives in a dream, waits at the window Wearing the face that she keeps in a jar by the door—who is it for?
This post has potentially manipulated dice roll results.
:2 + 6 + 2 + 8 = 18
Rollback Post to RevisionRollBack
Hello! Call me Tana or 타나 My pronouns are Any/All/BOC Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
Hello! Call me Tana or 타나 My pronouns are Any/All/BOC Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
This post has potentially manipulated dice roll results.
:1 + 2 + 8 + 5 = 16
Rollback Post to RevisionRollBack
Hello! Call me Tana or 타나 My pronouns are Any/All/BOC Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
This post has potentially manipulated dice roll results.
:3 + 2 + 2 + 6 = 13
Rollback Post to RevisionRollBack
Hello! Call me Tana or 타나 My pronouns are Any/All/BOC Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
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Oooops, to big
Hello! Call me Tana or 타나
My pronouns are Any/All/BOC
Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
16
How'd you get it that big?
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8 attempt: 5 + 5 + 7 + 5 = 22
Last to know and first to be blamed...
As a free action, can I regret my life choices?
17
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8 attempt: 2 + 7 + 7 + 1 = 17
So, what you're looking for are the odds of:
1) Rolling a d20, and reading the result (let's say it results in a 7)
2) Rolling a d6 <that> many times (in my example, 7 times), and having the result of those n rolls add up to 35? i.e. Roll #1 = 6, Roll #2 = 4, Roll #3 = 5, Roll #4 = 5, Roll #5 = 3, Roll #6 = 6, Roll #7 = 6....6+4+5+5+3+6+6 = 35.
That's beyond my stats skillz, so I asked an AI tool to explain that one. It's answer (and note: copy/pasting the formulas doesn't appear to work, so I'm just going to erase the formulas it's giving me!):
The problem requires calculating the overall probability of a target sum by considering all possible outcomes from the initial 20-sided die roll.
Let D20 be the result of the 20-sided die (from 1 to 20), and SD20 be the sum of D20 rolls of a 6-sided die. We are looking for the probability P(SD20=35).
The probability of any specific roll of the 20-sided die is P(D20 = n) = 1/20 for n = {1, 2, ..., 20}.
Using the Law of Total Probability, the overall odds are:
The minimum sum for n rolls of a 6-sided die is n, and the maximum is 6n. The sum of 35 is only possible if n <= 35 and 6n >= 35. The second condition requires n >= 35/6 = 5.833, so n must be at least 6.
Therefore, the summation only includes terms for n = 6 through n = 20.
The probability P(Sn = 35) is the number of ways to roll a total of 35 with n six-sided dice, divided by the total number of outcomes, 6^n.
The calculation performed by the tool is as follows:
Calculate the sum of the probabilities that n six-sided dice total 35, for n=6 to n=20. Approximately 0.2857101256698528
Calculate the Overall Probability: Divide the sum by 20 (the probability of any specific D20 roll). Approximately 0.014285506283492642
The overall odds that the results of all those rolls of the 6-sided die add up to total 35 is approximately 0.01428551, or about 1.428551%.
Last to know and first to be blamed...
As a free action, can I regret my life choices?
*round of applause*
28
Eleanor Rigby picks up the rice in the church where a wedding has been
Lives in a dream, waits at the window
Wearing the face that she keeps in a jar by the door—who is it for?
4d8 attempt: 7 + 5 + 4 + 4 = 20
Last to know and first to be blamed...
As a free action, can I regret my life choices?
22
Eleanor Rigby picks up the rice in the church where a wedding has been
Lives in a dream, waits at the window
Wearing the face that she keeps in a jar by the door—who is it for?
4d8 attempt:3 + 5 + 1 + 5 = 14.
Hiii :3 I’m Willow/Hazel, and I’m a bi genderfluid guy/girl/person.
Cancer Sun, Capricorn Moon, Virgo Rising are my big 3 signs.
Love all soulsbourne and soulslike games + metroidvanias. also play dbd but not much
Tokyo Ghoul is peak cinema, resident evil is the best, Creep is a good horror movie. Best movie OAT is thankskilling
:2 + 6 + 2 + 8 = 18
Hello! Call me Tana or 타나
My pronouns are Any/All/BOC
Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
20
Hi, I’m DrakenBrine, here’s my Sig and characters
I am The Grand Envisioner!
4d8=19
Hello! I am a perfectly sane gibberer. Hi! :D
Locations are dead, the Temple of Potassium has fallen but its ideals live on
A mysterious link of chain... (Extended signature). PRAISE JEFF THE EVIL ROOMBA! REALLY cool video.
One of the Warlock Patrons on the forums. Low, low price of your soul, firstborn child and liver!
Titles: The Echoing Story Spewer (Drummer), the Endless Maws (Isis), the Mad Murderer (PJ), more on my extended sig
:4 + 5 + 3 + 2 = 14
Hello! Call me Tana or 타나
My pronouns are Any/All/BOC
Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
(For a 32!!) Roll 4d8 = 5 + 3 + 2 + 5= 15
Next is 6d4 ... soon I hope.
4d8 attempt: 6 + 1 + 1 + 4 = 12
Last to know and first to be blamed...
As a free action, can I regret my life choices?
:1 + 2 + 8 + 5 = 16
Hello! Call me Tana or 타나
My pronouns are Any/All/BOC
Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.
4d8 attempt: 5 + 6 + 1 + 6 = 18
Last to know and first to be blamed...
As a free action, can I regret my life choices?
(For a 32!!) Roll 4d8 = 6 + 5 + 1 + 5= 17
Next is 6d4 ... soon I hope.
4d8 attempt: 8 + 8 + 8 + 2 = 26
Last to know and first to be blamed...
As a free action, can I regret my life choices?
:3 + 2 + 2 + 6 = 13
Hello! Call me Tana or 타나
My pronouns are Any/All/BOC
Disclaimer: Tana__ is not to be held responsible for any of the following events happening as a result of talking to Tana__, touching Tana__, or even just seeing Tana__: The rise of Tiamat, resurrection of Vecna, pissed-of genies, a complete and utter power change in the blood war, or a fate worse than a fate worse than total annihilation. Exist with Tana__ at your own risk.